Calculate the volume of 0.413 mol of hydrogen gas at a temperature of 20°C and a pressure of 1200 torr.

The volume is 6, 28 liters

Explanation:

The unit of pressure and temperature must be converted. 760 Torr = 1 atm and 0°C=273 K.     20+273=293K

760 Torr---1 atm

1200Torr--x= (1200 Torr x 1 atm)/760 Torr =1,58 atm

PV=nRT V=(nRT)/P

V= (0,413 mol x 0,082 L atm /K mol x 293K)/ 1,58 atm

V=6, 28 L

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