X litres of carbon monoxide is present at STP. It is completely oxidized to CO2. The volume of CO2 formed is 11.207L at STP. What is the value of X in litres?

11.207 L

Explanation:

In first place, we need to state the reaction:

2CO(g) + O₂(g) →  2CO₂(g)

Ratio is 2:2, so 2 moles of CO can produce 2 moles of CO₂

At STP conditions, 1 mol of any gas occupy 22.4 L. Therefore if our volume is 11.207 L we are having 0.500 moles of gas. Let's verify with the Ideal Gases Law:

1 atm . 11.207 L = n . 0.082 . 273.15K

1 atm . 11.207 L / 0.082 . 273.15K = 0.500 moles.

As ratio is 2:2, 0.500 moles of CO₂ came from 0.500 moles of CO

So the volume in STP, must be the same!

a. they must be certified by the avma.

explanation:

mark brainliest and have a great day!

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.