When the volume of a gas is changed from mL to 852 mL the temperature will change from 315c to 452c

The starting volume is 691 mL

Explanation:

The compete question is:

When the volume of a gas is changed from ___ mL to 852 mL, the temperature will change from 315 °C to 452 °C. What is the starting volume?

Write Charles Law and substitute values in:

   V1 / T1 = V2 / T2

    V1 / 588 K = 852 mL / 725 K

   V1 (725 K) = (852 mL) (588 K)

   V1 = 691 mL

Note the large °C values, trying to get you to forget to add 273. Remember, only Kelvin temperatures are allowed in the calculations.

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.