What is the amount of heat, in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22c to 66c

Answer :

the amount of heat,in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22°c to 66°c is 9.104 Joules.

Explanation:

The answer can be calculated using the formula

Q = mCрΔT

where

Q is the amount of heat required in joules to raise the temperature.

m is the mass of the sample in Kg.

Cp is the specific heat of the sample in J/Kg°C.

ΔT is the change in temperature required.

Here, m = 49.5-gram = 0.0495 kg

Cp = 4.18 J/Kg°C (for water)

T₁ = 22°C  ; T₂ = 66°C

ΔT =  66 - 22 = 44

Substituting values in Q = mCрΔT

Q = (0.0495)(4.18)(44)

                  Q = 9.104 J