Consider the Gibbs energies at 25 ∘ C. Substance Δ G ∘ f ( kJ ⋅ mol − 1 ) Ag + ( aq ) 77.1 Cl − ( aq ) − 131.2 AgCl ( s ) − 109.8 Br − ( aq ) − 104.0 AgBr ( s ) − 96.9 (a) Calculate Δ G ∘ rxn for the dissolution of AgCl ( s ) .

The ΔG° for the dissolution of AgCl solid is 55.7 kJ/mol.

Explanation:

The Gibbs free energy of the reaction is given by :

So for reaction :

Gibbs free energy of formation of silver ions =

Gibbs free energy of formation of chloride ions =

Gibbs free energy of formation of silver chloride solid=

The Gibbs free energy of the reaction of dissolution of AgCl : :

The ΔG° for the dissolution of AgCl solid is 55.7 kJ/mol.

the answer is c. nacl

the answer your looking for is c).