Write an equation for each acid or base showing its ionization in water, and write the equilibrium constant expression for the weak acid or base. Nitrous Acid, HNO2Ka = 4.0 x 10-4Acetic Acid, HC2H3O2Ka

HNO₂(aq) + H₂O(l)  ⇄  H₃O⁺(aq) +  NO₂⁻(aq)

Ka = [ H₃O⁺] . [NO₂⁻] / [HNO₂]

CH₃COOH(aq) + H₂O(l)  ⇄  CHCOO⁻ (aq) + H₃O⁺(aq)     Ka

Ka = [CHCOO⁻] . [H₃O⁺] / [CH₃COOH]

Remember to add the autoinization of water:

2H₂O(l) ⇄  OH⁻ (aq) + H₃O⁺(aq)              Kw

Explanation:

Nitrous acid → HNO₂ (weak acid)

The ionization in water is:

HNO₂(aq) → H⁺(aq) + NO₂⁻(aq)

Let's write the equilibrium:

HNO₂(aq) + H₂O(l)  ⇄  H₃O⁺(aq) +  NO₂⁻(aq)        Ka

Ka = [ H₃O⁺] . [NO₂⁻] / [HNO₂]

Acetic acid → CH₃COOH (weak acid)

Ionization in water: CH₃COOH(aq) → CHCOO⁻ (aq) + H⁺(aq)

Equilibrium: CH₃COOH(aq) + H₂O(l)  ⇄  CHCOO⁻ (aq) + H₃O⁺(aq)     Ka

Ka = [CHCOO⁻] . [H₃O⁺] / [CH₃COOH]

i think so it’s will be b yes i believe its

the answers are

c and c