A chemistry student adds a quantity of an unknown solid compound X to 750. mL of distilled water at 26.° C. After 10 minutes of stirring, all of the X has dissolved. The student then drains off the solution and evaporates the water under vacuum. A precipitate is left behind. The student washes, dries and weighs the precipitate. It weighs 0.012 kg.

Explanation:

The given data is as follows.

          X = 12 g,    Volume of water = 2 L,

Hence, solubility will be calculated as follows.

              = 6 g/L

As we know that 1 L contains 1000 ml. Hence, the calculated solubility will be converted into g/ml as follows.

               Solubility =

                               = 0.006 g/ml

Thus, we can conclude that the solubility of compound X in is 0.006 g/ml.

these nuts

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml