One mole of acetyl chloride was mixed with one mole of dimethylamine. After the reaction is complete, what species can be found in the mixture? Draw only the organic structures (i. e., omit inorganic ions). Show charges where necessary.

N,N-dimethylacetamide is formed.

Explanation:

It is an example of a nucleophilic addition-elimination reaction. Here dimethylamine acts as a nucleophile.In the first step, dimethyl amine gives nucleophilic addition reaction at carbonyl center of acetyl chloride.In the second step, removal of Cl atoms occurs.In the third step, deprotonation takes place from amino group to produce N,N-dimethylacetamide.Full reaction mechanism has been shown below.

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.

The question is incomplete. complete question is attached belowanswer: correct answer is option b  i.e.  solid particles  reason: filter paper has small pores, through which smaller particles can pass through. however, solid particles  have relatively larger size. hence, they are least likely to pass through.