. Calculate Ksp for copper oxalate (CuC2O4). Use your calculated copper ion concentration (0.0000027904 M) from the copper oxalate half-cell. Hint: This problem is also similar to practice problem 3.

Answer : The value of is

Explanation :

The solubility equilibrium reaction will be:

The expression for solubility constant for this reaction will be,

Concentration of copper ion = Concentration of oxalate ion = 0.0000027904 M

Therefore, the value of is

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

yes the answer is total mass in unchanged   : )