Enough of a monoprotic weak acid is dissolved in water to produce a 0.0144 0.0144 M solution. The pH of the resulting solution is 2.46 2.46 . Calculate the Ka for the acid.

The value of dissociation constant of the monoprotic acid is .

Explanation:

The pH of the solution = 2.46

Initially

0.0144         0      0

At equilibrium

(0.0144-x)       x       x

The expression if an dissociation constant is given by :

The value of dissociation constant of the monoprotic acid is .

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