Predict the effect of increasing the container volume on the amounts of each reactant and product in the following reactions: (a) CH3OH(l) <--> CH3OH(g) (b) CH4(g) + NH3(g) <--> HCN(g) + 3H2(g)

a) The reaction will shift to the right

b) The reaction will shift to the right

Explanation:

In the first case, we have on the left side we have a liquid state in the right side we have gas state, therefore the change in the volume will affect the gas state, if we increase the volume the pressure will decrease, so if we have less pressure. So,  we can have more compounds in the gas state. Thus, the first reaction would increase the amount of product.

In the second reaction, we have gas states in all the compounds. So, a decrease in pressure (or increase in volume) causes the system to evolve in the direction in which there are more moles, that is, where the number of gaseous moles is greater. In this case we have 2 moles in total in the left side (1 mol of and 1 mol of ) and in the right side we will have 4 moles (1 mol of and 3 mol of ). Therefore, the reaction will move to the right side.

i don't see a text, but i am gonna assume this *orbit* the curved path, usually elliptical, described by a planet, satellite, spaceship, etc., around a celestial body, as the sun.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2