Solid iron(II) hydroxide decomposes to form solid iron(II) oxide and liquid water. Write the balanced chemical equation for the reaction described. Phases are optional.

The balanced chemical equation that occurs when solid iron(II) hydroxide decomposes to form solid iron(II) oxide and liquid water is:

Fe(OH)₂(s) ⇒ FeO(s) + H₂O(l)

Let's consider the equation that occurs when solid iron(II) hydroxide decomposes to form solid iron(II) oxide and liquid water. This is a decomposition reaction, in which a substance decomposes into others.

Fe(OH)₂(s) ⇒ FeO(s) + H₂O(l)

This equation is already balanced with all the stoichiometric coefficients equal to 1.

The balanced chemical equation that occurs when solid iron(II) hydroxide decomposes to form solid iron(II) oxide and liquid water is:

Fe(OH)₂(s) ⇒ FeO(s) + H₂O(l)

You can learn more about decomposition reactions here:

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml