CO(g) + Cl2 (g) ⇌ COCl2 (g) Kp = 22.5 at 395 °C . A sample of COCl2 (g) is introduced into a constantvolume vessel at 395 °C and observed to exert an initial pressure of 0.351 atm. When equilibrium is established, what will be the total pressure within the vessel?

Explanation:

Hello,

In this case, it is convenient to rewrite the chemical reaction considering the COCl₂ as the reactant, so we must invert the equilibrium constant as shown below:

Thus, by introducing the change due to reaction's progress, one obtains:

Solving for via quadratic equation or solver, one obtains:

Clearly, the solution is for which the total pressure at equilibrium is:

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the number of protons in the nucleus of a given element. has slight luster and conducts electricity at high temperatures like metal.but like a nonmetal,boron is brittle and does not conduct electricity well at low temperatures. in graphite, carbon is a soft,brittle solid.it is reflective,ductile,or malleable.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2