In a titration, 15.65 milliliters of a KOH * (aq) ) solution exactly neutralized 10.00 milliliters of a 1.22 M HCl * (aq) solution . In the space below , show a correct numerical setup for calculating the molarity of the KOH * (aq) solution .

The molarity of the KOH solution is 0.780 M.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is KOH

are the n-factor, molarity and volume of base which is HCl.

We are given:

Putting values in above equation, we get:

The molarity of the KOH solution is 0.780 M.

answer: c.

explanation: