A galvanic cell at a temperature of 25.0°C is powered by the following redox reaction: →+3Cu+2aq2Als+3Cus2Al+3aq Suppose the cell is prepared with 7.97 M Cu+2 in one half-cell and 2.50 M Al+3 in the other. Calculate the cell voltage under these conditions. Round your answer to 3 significant digits.

Cell voltage under these condition is 2.02 V.

Explanation:

(Oxidation: ) ;

(Reduction: ) ;

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Overall:

Nernst equation for this cell reaction at -

Where, n is number of electron exchanged and species under third bracket represents concentration. Concentration of solids and liquids are excluded.

So, plug-in all the values in the above equation-

or,

So, cell voltage under these condition is 2.02 V

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