A 25 L cylinder contains 128 g of nitrogen gas at 10oC. How many grams of nitrogen must be added to increase the pressure to 5.00 atm assuming ideal gas behavior

Answer : The amount of nitrogen added must be, 22.64 grams.

Explanation :

First we have to calculate the moles of nitrogen gas.

Using ideal gas equation:

where,

P = Pressure of gas = 5.00 atm

V = Volume of gas = 25 L

n = number of moles  = ?

R = Gas constant =

T = Temperature of gas =

Putting values in above equation, we get:

Now we have to calculate the mass nitrogen gas.

Molar mass of nitrogen gas = 28 g/mol

Now we have to calculate the amount of nitrogen must be added.

Amount of nitrogen must be added = 150.64 g - 128 g

Amount of nitrogen must be added = 22.64 g

Thus, the amount of nitrogen added must be, 22.64 grams.

i believe the answer is 5,000