A sample of argon gas at a pressure of 0.859 atm and a temperature of 25.4 °C, occupies a volume of 15.0 liters. If the gas is allowed to expand at constant temperature to a volume of 18.7 liters, the pressure of the gas sample will be

The new pressure of the gas will be 0.689 atm

Explanation:

Step 1: Data given

Pressure of argon gas = 0.859 atm

Temperature = 25.4 °C = 298.55 K

Initial volume = 15.0 L

The volume will increase to 18.7 L

The temperature stays constant.

Step 2: Calculate the new pressure

P1*V1 = P2*V2

⇒with P1 = the initial pressure = 0.859 atm

⇒with V1 = the initial volume = 15.0 L

⇒with P2 = the new pressure = TO BE DETERMINED

⇒with V2 = the increased volume = 18.7 L

0.859 * 15.0 = P2 * 18.7

P2 = 0.689 atm

The new pressure of the gas will be 0.689 atm

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question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)