A 6.30 g 6.30 g sample of solid CaSO 4 ⋅ 2 H 2 O CaSO4⋅2H2O was heated such that the water turned to steam and was driven off. Assuming ideal behavior, what volume would that steam occupy at 1.00 atm 1.00 atm and 100.0 °C?

The volume of steam  V = 0.0107

Explanation:

Mass m = 6.3 gm = 0.0063 kg

Pressure = 1 atm = 101.325 k pa

Temperature = 100 °c = 373 K

From ideal gas equation,

P V = m R T --------- (1)

Put all the values in  the above equation we get

101.325 × V = 0.0063 × 0.462 × 373

⇒ V = 0.0107

This is the volume of steam.

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