How many moles of AlCl3 are in 2.25L of a 0.15 molar solution?

A. 0.07 moles
B. 0.15 moles
C. 0.34 moles
D. 15

Option C. 0.34 moles

Explanation:

Data obtained from the question include:

Molarity = 0.15M

Volume = 2.25L

Mole =

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 0.15 x 2.25

Mole = 0.34mole

The number of mole of AlCl3 present in the solution is 0.34mole.

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