If the pressure on 36.0 milliliters of a gas at STP is changed to a pressure of 25.3 kPa at constant temperature, the new volume of the gas is

The new volume of the gas is 144 mL.

Explanation:

At STP, the temperature is 273 K an pressure is 1 atm.

1 atm=101kPa

Given that initial volume V1=36 mL

Initial pressure P1=1atm=101 kPa

Final pressure P2=25.3kPa

We have to determine the final volume V2

According to Boyle's law

=144 mL

Final volume =144mL

0.144 litres or 144 ml is the volume f the pressure on 36.0 milliliters of a gas at STP is changed to a pressure of 25.3 kPa at constant temperature.

Explanation:

data given:

initial volume of gas = 36 ml 0r 0.036 litres

initial pressure at STP = 1 atm

final volume of the gas=?

final pressure = 25.3 kpa or 0.249 atm

Applying the Boyle's Law:

P1V1 = P2V2

0.036 X 1 = x X 0.249

X = 0.144 LITRES.

the volume of the gas is 0.144 litres.

The units are changed to to ml by multiplying it with 1000 so 144 ml is the volume of the gas.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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