How many moles of carbon are in 85.1 g of dipyrithione?

Express your answer to three significant figures and include the appropriate units.

3.38moles of carbon

Explanation:

We'll begin by obtaining the molar mass of the dipyrithione (C10H8N2O2S2). This is illustrated below:

Molar Mass of C10H8N2O2S2 = (12x10) + (8x1) + (14x2) + (16x2) + (32x2) = 120 + 8 + 28 + 32 + 64 = 252g/mol

Mass of C10H8N2O2S2 from the question = 85.1g

Number of mole of C10H8N2O2S2 =?

Number of mole = Mass/Molar Mass

Number of mole of C10H8N2O2S2 = 85.1/252 = 0.338mole

Now, if 1mole of dipyrithione contains 10 mole of carbon, therefore 0.338mole will contain = 0.338 x 10 = 3.38moles of carbon.