If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then I raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?

29.57L

Explanation:

The following were obtained from the question:

P1 (initial pressure) = 12atm

V1 (initial volume) = 23L

T1 (initial temperature) = 200K

P2 (final pressure) = 14atm

T2 (final temperature) = 300K

V2 (final volume) =?

Using the general gas equation P1V1/T1 = P2V2/T2, the final volume other wise called the new volume of the gas can easily be obtained as follow:

P1V1/T1 = P2V2/T2

12 x 23/200 = 14 x V2/300

Cross multiply to express in linear form as shown below:

200 x 14 x V2 = 12 x 23 x 300

Divide both side by 200 x 14

V2 = (12 x 23 x 300) /(200 x 14)

V2 = 29.57L

Therefore, the new volume of the gas is 29.57L

b. atoms in metallic solids are not arranged in a regular pattern

explanation: