0.450 mol of aluminum hydroxide is allowed to react with 0.550 mol of sulfuric acid; the reaction which ensues is:

2Al(OH)3(s) + 3H2SO4(aq) >Al2(SO4)3(aq) + 6H2O(l)

How many moles of H2O can form under these conditions?

a. 0.183
b. 0.367 mol
c. 1.10 mol
d. 0.250 mol
e. 0.125 mol

Option c. 1.10 moles

Explanation:

By the moles of the two reactants, we need to determine the limiting reactant.

If we only have the mass (or the moles) of one, we assume the other is in excess.

The reaction is: 2Al(OH)₃(s) + 3H₂SO₄(aq)  → Al₂(SO₄)₃(aq) + 6H₂O(l)

Let's work with stoichiometry: 2 moles of hidroxide react with 3 moles of sulfuric acid.

Then, 0.450 moles of hidroxide, will react with (0.450 . 3) / 2 = 0.675 moles of acid. Notice we have 0.550 of it, so we do not have enough acid to react, therefore the H₂SO₄ is the limiting reagent

Let's do another rule of three. Ratio is 3:6

3 moles of acid can produce 6 moles of water

Then, 0.550 moles of acid, will produce (0.550 . 6) / 3 = 1.1 moles of water

organisms are more likely to be more preserved in mud than sand because mud is moist and wet, while sand is very dry.

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: