Calculate the [OH−]

[H3O+]=3.0×10−9M

Thus the value of [OH⁻] calculated is = 3.3 × 10⁻⁶ M

Explanation:

Given:

Concentration of H₃O⁺ = 3.3 × 10⁻⁹ M

To Find:

Concentration of OH⁻ ion = ?

Solution:

From the value, and the concentration of H⁺ ion, we can find the concentration of hydroxyl ions, as is the product of the concentration of H⁺ and OH⁻ ions. We have the concentration of hydronium ion or H⁺ ion and value, dividing by the H⁺ ion concentration, we will get the concentration of OH⁻ ion as,

= [H₃O⁺] × [OH⁻]

    = 3.0 × 10⁻⁹ × [OH⁻]

Now we have to divide as,

[OH⁻] =   = 3.3 × 10⁻⁶ M

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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