How many moles of O2 are needed to react with 8.95 moles of Al?

6.71 moles of O₂

Explanation:

When the reactans are oxygen and aluminum, you produce aluminum oxide by this reaction:

4 Al + 3O₂  →  2Al₂O₃

The stoichiometry indicates that 4 moles of Al reacts with 3 moles of O₂.

Let's make a rule of three:

If 4 moles of Al reacts with 3 moles of O₂

Then, 8.95 moles of Al will react with (8.95 . 3) / 4 = 6.71 moles

We need 6.71 moles of O2 to react with 8.95 moles of Al

Explanation:

Step 1: Data given

Number of moles of Al = 8.95 moles

Step 2: The balanced equation

4Al + 3O2 → 2Al2O3

Step 3: Calculate moles number of moles O2 needed to react with Al

For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3

For 8.95 moles Al we need 3/4 * 8.95 = 6.71 moles O2

There will 8.95/2 = 4.48 moles Al2O3 be produced

We need 6.71 moles of O2 to react with 8.95 moles of Al

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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