2. When 400 J of heat is added to 5.6 g of olive oil at 23*C, the temperature increases to 87*C. What is the specific heat of the olive oil? (Show all work including the equation you use to solve). (3 points). See page 561 for an example.

The answer to your question is C = 1.116 J/g°C

Explanation:

Data

Q = 400 J

mass = 5.6 g

Temperature 1 = T1 = 23°C

Temperature 2 = T2 = 87°C

Specific heat = C = ?

Formula

Q = mC(T2 - T1)

- Solve for C

C = Q / m(T2 - T1)

- Substitution

C = 400 / 5.6 (87 - 23)

- Simplification

C = 400 / 5.6(64)

C = 400 / 358.4

- Result

C = 1.116 J/g°C

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.