Let the ED50 of a recreational drug be defined as the amount required for 50% of a test group to feel high or get a buzz. If the ED50 value of ethanol is 470 mg/kg body mass, what dose would a 70 kg party goer need to quickly consume in order to have a 50% chance of getting a buzz?If a bottle of beer contains about 13.9 g of ethanol, how many bottles of beer would a 70 kg party goer need to consume in order to have a 50% chance of getting a buzz?

If the lethal dose (LD50) for ethanol is 4,700 mg/kg, how many bottles of beer would a 70 kg party goer need to chug in order to have a 50% chance of dying?

A one liter bottle of Jack Daniels contains about 356 g of ethanol. How many 1.0 liter bottles of this whiskey would a 70 kg party goer need to chug in order to have a 50% chance of dying?

Explanation:

1) The ED50 value of ethanol = 470 mg per kg of person body = 470 mg/kg

Mass of person = 70 kg

Amount of ethanol required by person of 70 kg to get buzz:

A 70 kg party goer need to quickly consume in order to have a 50% chance of getting a buzz is 32,900 mg of ethanol.

Mass of ethanol in beer bottle = 13.9 g

Amount of ethanol required by person of 70 kg to get buzz:

1 mg = 0.001 mg

Bottles of beer would a 70 kg party goer need to consume:

Bottles of beer would a 70 kg party goer need to consume a 50% chance of getting a buzz is 2.

2)The LD50 value of ethanol = 4,700 mg per kg of person body = 4,700 mg/kg

Mass of person = 70 kg

Amount of ethanol required by person of 70 kg  to have a 50% chance of dying:

A 70 kg party goer need to quickly consume in order to have a 50% chance of dying is 329,000 mg of ethanol.

Mass of ethanol in Jack Daniels bottle = 356 g

Amount of ethanol required by person of 70 kg  to have a 50% chance of dying:

1 mg = 0.001 mg

Bottles of Jack Daniels would a 70 kg party goer need to consume to have a 50% chance of dying:

Bottles of  Jack Daniels would a 70 kg party goer need to consume to have a 50% chance of dying is 1.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation: