If the standard free energy change for the conversion of fructopyranose to fructofuranose is 1.7 kJ/mol, what fraction of the total fructose in solution is fructopyranose?

Explanation:

We know that relation between Gibb's free energy and temperature is as follows.

We are given that the value of is 1.7 kJ/mol.

And,  

      k =

         =

Since, k = 0.50357  and temperature is equal to 298 K.

Therefore,  

  = 0.50357

so, + 1 = 1.50357

          =

           =

          = 0.665

Therefore, we can conclude that 0.665 fraction of the total fructose in solution is fructopyranose.

the answer to your question is c