An aqueous 0.839 M acidic acid solution is prepared with a total volume of 0.500 L. The molecular weight of acidic acid is 60.05G/mole what mass of acetic acid in grams is needed for the solution

25.2 grams HOAc

Explanation:

For solution preparations a simple formula for determining amount of solute needed is ...

from solid stock => grams = Molarity x Volume (Liters) x formula wt of solute

∴ grams HOAc = M·V·f.wt = (0.839M)(0.500L)(60.05g/mol) = 25.2 grams HOAc

Mixing => Transfer gram wt of solute to mixing container and dilute up to but not to exceed total needed volume.

the correct option is c.

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