A solution is made by dissolving 1.8 moles of sodium chloride (NaCl) in 0.198
kilograms of water. If the molal boiling point constant for water (Kb) is 0.51 °C/m,
what would be the boiling point of this solution? Show all the steps taken to solve
this problem. (4 points)
[Hint: water boils at 100°C]

T(bp) = 104.64°C

Explanation:

molality = moles solute/Kg Solvent = 1.8 mol/0.198 Kg = 9.1 molal

ΔT(bp) = Kb·m = 0.51°C/m x 9.1 m = 4.64⁰C

Solution bp = 100°C + 4.64°C = 104.64°C

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )