Solve for partial pressure.

Partial pressure of He in the mixture of He, Ar and Ne is 0.128 atm in a total volume of 3 litres.

Explanation:

given that:

Pressure of He = 0.5 atm, volume = 1.5 L, Temperature = 298 K

Pressure of Ar = 2 atm, volume = 0.5 liter, temperature = 298K

Pressure of Ne = 1 atm, volume = 1 L, Temperature = 298 K

R = 0.0821 L atm /Kmole

Final volume of the container when all the gases are mixed = 3 litres.

temp remains constant.

Total pressure on the container=?

Frpm the formula,

P =

 =

 = 0.33 atm is the total pressure on the container.

The number of moles will be calculated by using PV=nRT

He

n =

  = 32 moles

Ar

n =

   = 24.4

Ne

n=

  = 24.4

total number of moles = 80.8 moles

mole fraction of helium in the gas mixture =

mole fraction of He = 0.39 moles

Applying the relation:

partial pressure of He = total pressure x mole fraction

                                       = 0.33 x 0.39

                                        = 0.128 atm.

Partial pressure of He in the mixture is 0.128 atm.

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

hope this

if you mean hydrogen and oxygen then water is the product