Consider the system at equilibrium. PCl 5 ( g ) − ⇀ ↽ − PCl 3 ( g ) + Cl 2 ( g ) How will increasing the concentration of PCl5 shift the equilibrium? to the left to the right no effect How will increasing the concentration of PCl3 shift the equilibrium? to the right no effect to the left How will increasing the pressure by adding argon gas to the reaction mixture, while maintaining a constant volume, shift the equilibrium? to the right to the left no effect

1) Increasing the concentration of shift the equilibrium to the right side.

2) Increasing the concentration of shift the equilibrium to the left.

3) increasing the pressure by adding argon gas to the reaction mixture, while maintaining a constant volume will have no effect.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

On increasing concentration of reactants :

When concentration of reactants are increased the equilibrium shifts in forward direction(right) to reestablish itself and concentration of products increases with it.

On increasing concentration of products :

When concentration of products are increased the equilibrium shifts in backward direction (left) to reestablish itself and concentration of reactants increases with it.

On adding inert gas at constant volume.

No change will occur because adding inert gas will increase the total pressure of the system not the partial pressure of the components of the equilibrium.

1) Increasing the concentration of shift the equilibrium to the right side.

2) Increasing the concentration of shift the equilibrium to the left.

3) increasing the pressure by adding argon gas to the reaction mixture, while maintaining a constant volume will have no effect.

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the have energy higher than those in the orbital while lower than those of the orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the orbital is therefore filled right after orbitals and before orbitals.  

potassium has electron configuration and calcium . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the and should be highlighted as well.