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60.6

Explanation:

Given data:

Mass of Si = 10 g

Mass of Cl₂ = 60.0 g

Mass of SiCl₄ = ?

Solution:

Chemical equation:

Si + 2Cl₂  →   SiCl₄

Number of moles of Si:

Number of moles = mass/ molar mass

Number of moles = 10 g/28 g/mol

Number of moles = 0.357 mol

Number of moles of Cl₂ :

Number of moles = mass/ molar mass

Number of moles = 60 g/70.9 g/mol

Number of moles = 0.846 mol

Now we will compare the moles of SiCl₄ with both reactants.

                               Cl₂              :            SiCl₄

                                2                :              1

                             0.846           :           1/2×0.846=0.423

                                Si               :           SiCl₄

                                 1                 :            1

                                0.357         ;          0.357

Number of moles of SiCl₄ produce by Si are less so it will limiting reactant and limit the yield of SiCl₄.

Mass of SiCl₄:

Mass = number of moles × molar mass

Mass = 0.357 mol  × 169.8 g/mol

Mass = 60.6 g

1 is the answer to this problem