Chemistry, 25.03.2020 05:35 Squara

Because of the toxicity of mercury compounds, mercury(I) chloride is used in antibacterial salves. The mercury(I) ion Hg22+ consists of two bound Hg+ ions. How many grams of mercury(I) chloride are needed to saturate 4900 km3 of water (the volume of Lake Michigan)? (Ksp = 1.5 × 10−18).

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Answer from: isabelsmhl

$1.668\times 10^{12}$ grams of mercury(I) chloride are needed to saturate 4900 km^3 of water .

Explanation:

$Hg_2Cl_2\rightleftharpoons Hg_2^{2+}+2Cl^-$

S 2S

Solubility product of mercury (I) chloride= $K_{sp}=1.5\times 10^{-18}$

The expression of solubility product is given as:

$K_{sp}=[Hg_2^{2+}][Cl^-]^2$

$K_{sp}=[S][2S]^2=4S^2$

$1.5\times 10^{-18}=4S^3$

$S= 7.211\times 10^{-7} M$

Volume of water V = 4900 km^3

$km^3=10^{12} L$

$V=4900\times 10^{12} L$

Moles of mercury(I) chloride in solution= n

$n=S\times V=7.211\times 10^{-7} M\times 4900\times 10^{12} L$

Mass of n moles of mercury(I) chloride: m

$=7.211\times 10^{-7} M\times 4900\times 10^{12} L\times 472 g/mol$

$m= 1.668\times 10^{12} g$

$1.668\times 10^{12}$ grams of mercury(I) chloride are needed to saturate 4900 km^3 of water .

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

= 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

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