Chemistry, 25.03.2020 16:49 obastwin2

A 1.167 g sample contains only vitamin C (C6H8O6) and sucralose (C12H19Cl3O8). When the sample is dissolved in water to a total volume of 35.9 mL, 35.9 mL, the osmotic pressure of the solution is 3.67 atm 3.67 atm at 285 K. 285 K. What is the mass percent of vitamin C and sucralose in the sample?

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Answer from: kebo63

Mass % Vitamin C: 73.3%

Mass % sucralose: 26.7%

Explanation:

The mass of Vitamin C (a) + Sucralose (b) is 1.167g. Thus, it is possible to write:

a + b = 1.167g (1)

The osmotic pressure formula in solution is:

π = i×M×R×T

Where π is osmotic pressure (3.67atm), i is Van't Hoff factor (1 for Vitamin C and Sucralose),M is molarity of solution (moles / 0.0359L), R is gas constant (0.082atmL/molK) and T is temperature (285K). Replacing:

3.67atm = 1 × moles / 0.0359L × 0.082atmL/molK × 285K

0.00564 = moles of solution (Moles of Vitamin C + Sucralose)

These moles can be written as:

0.00564 mol = a× (1mol / 176.12g) + b×(1mol / 397.64g) (2)

Where 176.12 is molar mass of vitamin C and 397.64 is molar mass of sucralose

Replacing (1) in (2)

0.00564 = (1.167 - b) / 176.12 + b / 397.64

0.000986 = 0.003163 b

0.312g = b. → Mass of sucralose.

Mass of Vitamin C → 1.167g - 0.312g = 0.855g

Thus, Mass percent is:

Mass % Vitamin C: 0.855g / 1.167g ×100 = 73.3%

Mass % sucralose: 0.312g / 1.167g ×100 = 26.7%

Answer from: chiquita77

Explanation:

Mass of sucrose and sucralose = 1.167 g

Molar mass of sucrose = (C6H8O6)

= (12×6) + (8×1) + (6×16)

= 176 g/mol

Molar mass of = C12H19Cl3O8

= (12×12) + (19×1) + (35.5×3) + (16×8)

= 397.5 g/mol

Pressure, P = 3.67 atm

Volume, V = 35.9 ml

Temperature, T = 285 K

Using PV = nRT

nt = (3.67 × 35.9 × 10^-3)/(285 × 0.08205)

= 0.00563 moles.

Molar mass = mass/number of moles

let x be the mass of sucralose

nt = n1 + n2

0.00563 = (1.167 - x)/176 + x/397.5

0.00563 = 0.00663 - 0.0057x + 0.00252x

0.001 = 0.00318x

x = 0.3145 g

Mass % = mass of sample/total mass × 100

Sucralose mass % = 0.3145/1.167 × 100

= 26.95%

Sucrose mass % = (1.167 - 0.3145)/1.167 × 100

= 73.05%

Answer from: Quest

Coal i believe hope this

Answer from: Quest

The answer to your question really depends on three things: how much water you have, how cold it is to start out, and how cold the things around it are. water actually freezes when it gets to 32 degrees fahrenheit (0 degrees celsius), but the time it takes to get there may be different. let's start with the first. if you take two glasses, and fill one with a tiny bit of water, and the other about halfway, then put them both in the freezer, the one with less water will freeze first (you can try this at home, but i recommend using plastic cups and not glass ones). now let's move on to the second part. let's say you have two glasses, and you fill one with really cold water that has been in the refrigerator, and the other with really hot water from the sink. if you put both of them in the freezer, the one that started out colder will freeze first. for the third part, let's imagine that you have two glasses with the same amount of water in them, and the water is at the same temperature. imagine putting one outside on a really really cold day in georgia, and having a friend in alaska put one outside on the same day. since it would be so much colder in alaska, the glass of water there would freeze before yours. so, if you took a tiny bit of really cold water in a glass, and put it outside on a cold day in alaska, it would freeze a lot faster than a big glass of hot water outside on a cold day in georgia.

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A 1.167 g sample contains only vitamin C (C6H8O6) and sucralose (C12H19Cl3O8). When the sample is di...

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