5. Sucrose is readily hydrolysed to glucose and fructose in acidic solution. The hydrolysis is often monitored by measuring the angle of rotation of plane-polarized light passing through the solution. From the angle of rotation the concentration of sucrose can be determined. An experiment on the hydrolysis of sucrose in 0.50m HCl(aq) produced the following data: t/min 0 14 39 60 80 110 140 170 210 [sucrose] 0.316 0.300 0.274 0.256 0.238 0.211 0.190 0.170 0.146 Determine the rate constant of the reaction and the half-life of a sucrose molecule.

ln a = −1.1491 − 3.6697 × 10−3t

Explanation:  

The first order integrated rate law is

kt = ln (a0/a)

ln a=ln a0 − kt  

A plot of ln(a) vs. t would, therefore, yield a straight line whose slope will be equal to −k. The result of the linear regression (Excel can easily do this) is

ln a = −1.1491 − 3.6697 × 10−3t

Therefore, the rate constant is 3.6697 × 10−3 s−1. Note that the intercept has approximately the correct value of ln a0.

is it a purebred? it looks more like a red nose, but it doesn't have the red could it be a staffordshire bull terrior? unsure if that's the right name for it sorry

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !