The combustion of propane (C3H8) produces CO2 and H2O: C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g) The reaction of 1.0 mol of O2 will produce mol of H2O.

0.8 moles of H2O

Explanation:

C3H8 (g) + 502 (g) → 3C02 (g) + 4H2O(g)

Propane + Oxygen → Carbon dioxide + water

In the reaction above,

5 moles of O2 produce 4 moles of H2O

1.0 mol of O2 will produce Z moles of H2O

To get the value of Z, cross multiply

Z moles x 5 moles = 4 moles x 1.0 moles 5Z = 4

Z = 4/5

Z = 0.8

Thus, 1.0 moles of O2 will produce 0.8 moles of H2O

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

"record the time to complete a chemical reaction" would most likely be part of a lab procedure.