A 6.87-L sample of gas has a pressure of 0.732 atm and a temperature of 95 °C. The sample is allowed to expand to a volume of 9.22 L and is cooled to 44 °C. Calculate the new pressure of the gas, assuming that no gas escaped during the experiment.

The new pressure of the gas, assuming that no gas escaped during the experiment is 0.470 atm

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas = 0.732 atm

= final pressure of gas = ?

= initial volume of gas = 6.87 L

= final volume of gas = 9.22 L

= initial temperature of gas =

= final temperature of gas =

Now put all the given values in the above equation, we get:

Thus the new pressure of the gas, assuming that no gas escaped during the experiment is 0.470 atm

1 is the answer to this problem