After identifying the anions (negative ions), in each of the following
compounds, write the formula for the compound in either the soluble
beaker or insoluble box in the correct anion section, on the other page.
AgCl
NaCzH302
Lici
H2SO4
Pb(NO3)2
CaCO3
NaOH
Ca(OH)2
КОН
Cu(OH)2
CaSO4
HCI
(NH4)3PO4
Ca(NO3)2
MgCO3

yes

ya te ayud espera

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2