A sample of oxygen gas has a volume of 151 mL when its pressure is 0.947 atm. what will the volume of the gas be at a pressure of 0.987 atm if the temperature remains constant?

151.2mL

Explanation:

Initial volume V1 = 151mL

Initial pressure P1 = 0.947atm

Final volume V2 = ?

Final pressure P2 = 0.948atm

According to Boyle's law, the volume of a fixed mass of a gas is inversely proportional to the pressure when temperature is constant.

Thus, Boyles' Law is expressed as:

P1/V1 = P2/V2

0.947/151 = 0.948/V2

To get the value of V2, cross multiply

0.947 x V2 = 0.948 x 151

0.947V2 = 143.148

Divide both sides by 0.947

0.947V2/0.947 = 143.148/0.947

V2 = 151.159 mL (Round to nearest tenth 151.2mL

Thus, the final volume is 151.2mL

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