Sample of helium gas has a volume of 200.0 mL at 0.960 atm. What pressure, in atm, is needed to reduce the volume at constant temperature to 50.0 mL? *

The  new pressure is 3,84 atm

Explanation:

We use Boyle Mariotte's formula: for a given mass of gas at constant temperature, the pressure and volume vary inversely proportionally. We convert the unit volume in ml into L: 200/1000=0,2 L and 50/1000=0,05L

P1xV1=P2xV2

P2= (P1xV1)/V2= (0,96 atm x 0,2L)/0,05 L= 3,84 atm

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