Methane is burned with dry air in a steady-flow combustor. The volumetric analysis of the products on a dry basis is 5.2% CO2, 0.33% CO, 11.24% O2, and 83.23% N2. The methane and air enter the combustor at 298 K and 1 atm and the products exit at 1200 K and 1 atm. Determine (a) the air-fuel ratio, (b) the equivalence ratio, (c) the dew point of the product mixture, (d) the amount of energy transfer as heat (in kJ/kmol CH4), and (e) the entropy production rate during the combustion process (in kJ/kmol-K). The surroundings are at 298 K and 1 atm. Assume ideal gas behavior, and make allowance for variations in species specific heats with temperature.

answer

the ions in solute supperate from eachouthere

answer:

the reaction is type of combination reaction.

explanation:

on the product side, there are 2 molecules of bonded to fe   which means one atom of fe are combined two molecules of . so, balanced chemical equation becomes :

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied