Al2(SO4)3 + Ca(OH)2 → Al(OH)3 + CaSO4

Hey there!

I assume you want this equation balanced.

Al₂(SO₄)₃ + Ca(OH)₂ → Al(OH)₃ + CaSO₄

Let's start by balancing the polyatomic ions, starting with SO₄.

There are 3 on the left and 1 on the right, so let's add a coefficient of 3 in front of the CaSO₄.

Al₂(SO₄)₃ + Ca(OH)₂ → Al(OH)₃ + 3CaSO₄

Now let's balance the polyatomic ion OH.

There are 2 on the left and 3 on the right, so let's put a coefficient of 3 in front of Ca(OH)₂ and a coefficient of 2 in front of Al(OH)₃.

Al₂(SO₄)₃ + 3Ca(OH)₂ → 2Al(OH)₃ + 3CaSO₄

Now let's balance Al.

There are 2 on the left and 2 on the right, so Al is already balanced.

Lastly, let's balance Ca.

There are 3 on the left and 3 on the right, so Ca is already balanced.

This means we're done! Here's the final balanced equation:

Al₂(SO₄)₃ + 3Ca(OH)₂ → 2Al(OH)₃ + 3CaSO₄  

Hope this helps!

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3