A solution is prepared by dissolving 0.23 mol of hydrazoic acid and 0.27 mol of sodium azide in water sufficient to yield 1.00 L of solution. The addition of 0.05 mol of NaOH to this buffer solution causes the pH to increase slightly. The pH does not increase drastically because the NaOH reacts with the present in the buffer solution. The Ka of hydrazoic acid is 1.9 ⋅ 10-5.

The pH does not increase drastically because the NaOH reacts with the _HYDRAZOIC ACID__ present in the buffer solution.

Explanation:

NaOH reacts with the hydrazoic acid in the buffer

HN3 + OH? --> H2O + N3-

If you put acid in, it will react with N3-. Here is the equation below:

N3- + H+ --> HN3

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explanation:

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