A sample of neon occupied a volume of 15.0L at a temp 30.0(C. if the temp were to increase by 15(C, what would be the volume of the neon under this new condition ?

22.5L will be the new volume for the gas

Explanation:

Pressure and number of moles remains constant.

When the temperature for a sample of gas is increased, the volume will also be increased, acording to this relation:

V₁ / T₁ = V₂ / T₂

15L / 30°C  =  V₂ / 45°C

(15L / 30°C ). 45°C = 22.5L

We assume Ar, as an Ideal Gas

When the temperature increases with 15 °C the new volume will be 15.7 L

Explanation:

Step 1: Data given

Initial volume of the neon = 15.0 L

Initial temperature of the neon = 30.0 °C = 303 K

The temperature is increased by 15°C = 318 K

Step 2: Calculate the new volume

V1/T1 = V2/T2

⇒with V1 = the initial volume of neon = 15.0 L

⇒with T1 = the initial temperature = 303 K

⇒with V2 = the final volume = TO BE DETERMINED

⇒with T2 = the increased temperature = 318 K

15.0 L / 303 K = V2 / 318 K

V2 = (15.0 L/ 303 K) * 318 K

V2 = 15.7 L

When the temperature increases with 15 °C the new volume will be 15.7 L

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