What is the percent by volume of isopropyl alcohol in a solution that contains 45 ml of isopropyl alcohol in 1.4 L of water?

Hey there!

There are 1000 mL in a liter.

1.4 L + 0.045 L = 1.445 L

In total there is 1.445 L of the solution.

To find the percent of isopropyl alcohol, divide the amount of isopropyl alcohol by the total amount.

0.045 ÷ 1.445 = 0.0311

Convert to a percent.

3.11%

Hope this helps!  

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole