What is the volume of 0.366 moles of helium collected at 25 C and a
pressure of 0.98 atm?*

V = 9.14 L

Explanation:

Given data:

Volume of helium = ?

Number of moles = 0.366 mol

Temperature = 25°C (25+273 = 298 K)

Pressure of gas = 0.98 atm

Solution:

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K

V = nRT/P

V = 0.366 mol ×  0.0821 atm.L/ mol.K  × 298 K / 0.98 atm

V = 8.95 L / 0.98

V = 9.14 L

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i  

the answer would be b i believe