A flask contains 0.83mol of neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is the volume of the neon gas?

5.66 dm3

Explanation:

Given that:

Volume of neon gas = ?

Temperature T = 35°C

Convert Celsius to Kelvin

(35°C + 273 = 308K)

Pressure P = 0.37 atm

Number of moles N = 0.83 moles

Note that Molar gas constant R is a constant with a value of 0.0082 ATM dm3 K-1 mol-1

Then, apply ideal gas equation

pV = nRT

0.37atm x V = 0.83 moles x 0.0082 atm dm3 K-1 mol-1 x 308K

0.37 atm x V = 2.096 atm dm3

V = (2.096 atm dm3 / 0.37atm)

V = 5.66 dm3

Thus, the volume of the neon gas is 5.66 dm3

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .