Which equation shows how to calculate how many grams (g) of koh would be needed to fully react with 4 mol mg(oh)2? the balanced reaction is: . mgcl2 + 2koh mg(oh)2 + 2kcl

The mass of KOH will be 448 grams.

Explanation:

For the given chemical reaction:

By Stoichiometry of the reaction:

1 mole of magnesium chloride reacts with 2 moles of potassium hydroxide.

So, 4 moles of magnesium chloride will react with = of potassium hydroxide.

To calculate the number of moles, we use the equation:

Moles of potassium hydroxide = 8 mol

Molar mass of potassium hydroxide = 56 g/mol

Putting values in above equation, we get:

Hence, the mass of KOH will be 448 grams.

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-