Initially the concentration of H2 is 2.0M , I2 is 2.0M and HI is 8.0M. The vessel is heated up to 675 degrees at equilibrium the concentration of HI changes to become 6.0M. Calculate the value of k at this temperature.

The value of K at this temperature = 2.25

Explanation:

According to question the equilibrium reaction is

                                           H₂(g) + I₂(g) ⇄ 2 HI(g)

       Initial concentration   2           2             8

         At equilibrium     2 + 2x     2 + 2x          8 - 2x

At equilibrium concentration of HI changes to become 6 Molar

                      So 8 - 2x = 6

                      or, x = 1

So concentration of H₂ = 2 + 2 x 1 = 4 molar

concentration of I₂ = 2 + 2 x 1 = 4 molar

                  Kc =

     ⇒          Kc =

     ⇒         Kc = = 2.25

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.